#LyX 1.4.3 created this file. For more info see http://www.lyx.org/ \lyxformat 245 \begin_document \begin_header \textclass article \begin_preamble %% % \setlength{\topmargin}{-.8in} \setlength{\headheight}{0in} \setlength{\headsep}{0in} \setlength{\footskip}{0in} \setlength{\evensidemargin}{-.5in} \setlength{\oddsidemargin}{-.5in} \setlength{\textheight}{9.5in} \setlength{\textwidth}{7in} \setlength{\parindent}{0in} % \newcommand{\rank}{\operatorname{rank}} \newcommand{\dimn}{\operatorname{dim}} \newcommand{\spann}{\operatorname{span}} \newcommand{\vc}[1]{\mathbf{#1}} \end_preamble \language english \inputencoding auto \fontscheme default \graphics default \paperfontsize 12 \spacing single \papersize default \use_geometry false \use_amsmath 2 \cite_engine basic \use_bibtopic false \paperorientation portrait \secnumdepth 3 \tocdepth 3 \paragraph_separation indent \defskip medskip \quotes_language english \papercolumns 1 \papersides 1 \paperpagestyle empty \tracking_changes false \output_changes true \end_header \begin_body \begin_layout Standard \series bold Exam\InsetSpace ~ 3 \hfill Math\InsetSpace ~ 314 \hfill Fall 2006 \newline Name: \series default \begin_inset ERT status collapsed \begin_layout Standard \backslash rule{2.4in}{.01in} \end_layout \end_inset \hfill \series bold Score: \series default \begin_inset ERT status collapsed \begin_layout Standard \backslash rule{1in}{.01in} \end_layout \end_inset \end_layout \begin_layout Standard \begin_inset ERT status collapsed \begin_layout Standard \backslash hspace{.25in} \end_layout \end_inset \shape italic Instructions: \begin_inset ERT status collapsed \begin_layout Standard \backslash /{} \end_layout \end_inset \shape default Show your work in the spaces provided below for full credit. Use the reverse side for additional space, \shape italic but clearly so indicate. \begin_inset ERT status collapsed \begin_layout Standard \backslash /{} \end_layout \end_inset \shape default You must clearly identify answers and show supporting work to receive any credit. Exact answers (e.g., \begin_inset Formula $\pi$ \end_inset ) are preferred to inexact (e.g., \begin_inset Formula $3.14$ \end_inset ). Point values of problems are given in parentheses. Notes or text in \emph on any \emph default form not allowed. Calculator is allowed. \newline \begin_inset ERT status collapsed \begin_layout Standard \backslash rule[.3in]{7in}{.01in} \end_layout \end_inset \end_layout \begin_layout Standard \begin_inset ERT status collapsed \begin_layout Standard \backslash vspace{-.1in} \end_layout \end_inset (25) \series bold 1. \series default Let \begin_inset Formula $\mathbf{v}_{1}=\left(1,1,0\right))$ \end_inset , \begin_inset Formula $\mathbf{v}_{2}=\left(-1,1,1\right)$ \end_inset , \begin_inset Formula $\mathbf{v_{3}}=\left(1/2,-1/2,1\right)$ \end_inset and \begin_inset Formula $\mathbf{v}=\left(1,2,-2\right)$ \end_inset . \end_layout \begin_layout Standard (a) Find the norm of \begin_inset Formula $\mathbf{v}$ \end_inset . \end_layout \begin_layout Standard \begin_inset ERT status collapsed \begin_layout Standard \backslash vspace{1.2in} \end_layout \end_inset (b) Find the cosine of the angle between the vectors \begin_inset Formula $\mathbf{v}$ \end_inset and \begin_inset Formula $\mathbf{v}_{1}.$ \end_inset \end_layout \begin_layout Standard \begin_inset ERT status collapsed \begin_layout Standard \backslash vspace{1.2in} \end_layout \end_inset (c) Verify the CBS inequality for the pair of vectors \begin_inset Formula $\mathbf{v},\mathbf{v}_{2}.$ \end_inset \end_layout \begin_layout Standard \begin_inset ERT status collapsed \begin_layout Standard \backslash vspace{1.7in} \end_layout \end_inset (d) Show \begin_inset Formula $\mathbf{v}_{1},\mathbf{v}_{2},\mathbf{v_{3}}$ \end_inset is an orthogonal set (hence a basis of \begin_inset Formula $\mathbb{R}^{3}$ \end_inset ). \end_layout \begin_layout Standard \begin_inset ERT status collapsed \begin_layout Standard \backslash vspace{1.8in} \end_layout \end_inset (e) Find the coordinates of \begin_inset Formula $\mathbf{v}$ \end_inset relative to this basis. \end_layout \begin_layout Standard \begin_inset ERT status collapsed \begin_layout Standard \backslash clearpage \end_layout \end_inset \series bold \series default (10) \series bold 2. \series default Set up and solve the normal equations for the system \begin_inset Formula $A\mathbf{x}=\mathbf{b}$ \end_inset , where \begin_inset Formula $A=\left[\mathbf{v}_{1},\mathbf{v}_{2}\right]$ \end_inset , \begin_inset Formula $\mathbf{v}_{1}=\left(1,1,0\right))$ \end_inset , \begin_inset Formula $\mathbf{v}_{2}=\left(-1,1,1\right)$ \end_inset and \begin_inset Formula $\mathbf{b}=\left(2,1,1\right)$ \end_inset . Is the least squares solution a genuine solution? \end_layout \begin_layout Standard \begin_inset ERT status collapsed \begin_layout Standard \backslash vspace{4.0in} \end_layout \end_inset \end_layout \begin_layout Standard \series bold 3. \series default (14) Find an eigensystem for the matrix \begin_inset Formula $A=\left[\begin{array}{ccc} 1 & 0 & 0\\ -2 & 1 & 0\\ 1 & 0 & 1\end{array}\right].$ \end_inset Give reasons why the matrix \begin_inset Formula $A$ \end_inset is or is not diagonalizable. \end_layout \begin_layout Standard \begin_inset ERT status collapsed \begin_layout Standard \backslash clearpage \end_layout \end_inset (24) \series bold 4. \series default Matrix \begin_inset Formula $A=\left[\begin{array}{cc} -2 & 2\\ 2 & 1\end{array}\right]$ \end_inset has eigenvalues \begin_inset Formula $-3$ \end_inset , \begin_inset Formula $2$ \end_inset , and eigenvectors \begin_inset Formula $\mathbf{v}_{1}=\left(2,-1\right)$ \end_inset , \begin_inset Formula $\mathbf{v}_{2}=\left(1,2\right)$ \end_inset . \end_layout \begin_layout Standard (a) Use this information to find a diagonalizing matrix \begin_inset Formula $P$ \end_inset for \begin_inset Formula $A$ \end_inset and resulting diagonal matrix \begin_inset Formula $D$ \end_inset . \end_layout \begin_layout Standard \begin_inset ERT status collapsed \begin_layout Standard \backslash vspace{3.1in} \end_layout \end_inset (b) Use (a) to find a formula for powers of \begin_inset Formula $A$ \end_inset in terms of powers of eigenvalues of \begin_inset Formula $A.$ \end_inset \end_layout \begin_layout Standard \begin_inset ERT status collapsed \begin_layout Standard \backslash vspace{3.8in} \end_layout \end_inset (c) Find unit vectors \begin_inset Formula $\mathbf{u}_{1}$ \end_inset , \begin_inset Formula $\mathbf{u}_{2}$ \end_inset in the directions of \begin_inset Formula $\mathbf{v}_{1}$ \end_inset , \begin_inset Formula $\mathbf{v}_{2}$ \end_inset , respectively, and exhibit an orthogonal matrix \begin_inset Formula $U$ \end_inset that diagonalizes \begin_inset Formula $A$ \end_inset . \end_layout \begin_layout Standard \begin_inset ERT status collapsed \begin_layout Standard \backslash clearpage \end_layout \end_inset (18) \series bold 5. \series default Fill in the blanks, or answer T/F: \end_layout \begin_layout Standard (a) If \begin_inset Formula $A$ \end_inset is a real matrix, then \begin_inset Formula $A^{T}A$ \end_inset is symmetric (T/F) \begin_inset ERT status collapsed \begin_layout Standard \backslash rule{1in}{.01in} \end_layout \end_inset . \end_layout \begin_layout Standard \begin_inset ERT status collapsed \begin_layout Standard \backslash vspace{.2in} \end_layout \end_inset (a) Eigenvalues of a matrix cannot be zero (T/F) \begin_inset ERT status collapsed \begin_layout Standard \backslash rule{1in}{.01in} \end_layout \end_inset . \end_layout \begin_layout Standard \begin_inset ERT status collapsed \begin_layout Standard \backslash vspace{.2in} \end_layout \end_inset (b). If \begin_inset Formula $Q$ \end_inset is an \begin_inset Formula $n\times n$ \end_inset orthogonal matrix and \begin_inset Formula $\mathbf{v}\in\mathbb{R}^{n},$ \end_inset then \begin_inset Formula $\left\Vert Qv\right\Vert =\left\Vert v\right\Vert $ \end_inset (T/F) \begin_inset ERT status collapsed \begin_layout Standard \backslash rule{1in}{.01in} \end_layout \end_inset . \end_layout \begin_layout Standard \begin_inset ERT status collapsed \begin_layout Standard \backslash vspace{.2in} \end_layout \end_inset (c) If \begin_inset Formula $\rho(A)<1$ \end_inset and \begin_inset Formula $\mathbf{x}^{(k+1)}=A\mathbf{x}^{(k)},$ \end_inset then \begin_inset Formula $\lim_{k\rightarrow\infty}\mathbf{x}^{(k)}$ \end_inset equals \begin_inset ERT status collapsed \begin_layout Standard \backslash rule{2in}{.01in} \end_layout \end_inset . \end_layout \begin_layout Standard \begin_inset ERT status collapsed \begin_layout Standard \backslash vspace{.2in} \end_layout \end_inset (d) The matrix \begin_inset Formula $\frac{1}{\sqrt{3}}\left[\begin{array}{cc} 1+i & i\\ i & 1-i\end{array}\right]$ \end_inset is not unitary (T/F) \begin_inset ERT status collapsed \begin_layout Standard \backslash rule{2in}{.01in} \end_layout \end_inset . \end_layout \begin_layout Standard \begin_inset ERT status collapsed \begin_layout Standard \backslash vspace{.2in} \end_layout \end_inset (e) The matrix \begin_inset Formula $\left[\begin{array}{ccc} 2 & 1 & 0\\ 0 & 1 & 1\\ 0 & 0 & 0\end{array}\right]$ \end_inset is diagonalizable because \begin_inset ERT status collapsed \begin_layout Standard \backslash rule{3in}{.01in} \end_layout \end_inset . \end_layout \begin_layout Standard \begin_inset ERT status collapsed \begin_layout Standard \backslash vspace{.2in} \end_layout \end_inset (f) The matrix \begin_inset Formula $\left[\begin{array}{cc} 1 & i\\ -i & 3\end{array}\right]$ \end_inset is unitarily diagonalizable because \begin_inset ERT status collapsed \begin_layout Standard \backslash rule{2.5in}{.01in} \end_layout \end_inset . \end_layout \begin_layout Standard (g) Every orthonormal set of vectors is linearly independent (T/F) \begin_inset ERT status collapsed \begin_layout Standard \backslash rule{0.8in}{.01in} \end_layout \end_inset . \end_layout \begin_layout Standard \begin_inset ERT status collapsed \begin_layout Standard \backslash vspace{.1in} \end_layout \end_inset (h) The component of \begin_inset Formula $\mathbf{u}=(1,2,0)$ \end_inset along the vector \begin_inset Formula $\mathbf{v}=(1,1,1)$ \end_inset is \begin_inset Formula $\operatorname{comp}_{\mathbf{v}}\left(\mathbf{u}\right)=$ \end_inset \begin_inset ERT status collapsed \begin_layout Standard \backslash rule{1.3in}{.01in} \end_layout \end_inset . \end_layout \begin_layout Standard \begin_inset ERT status collapsed \begin_layout Standard \backslash vspace{.1in} \end_layout \end_inset (9) \series bold 6. \series default The vector \begin_inset Formula $\mathbf{v}_{1}=\left(1,1\right)$ \end_inset is an eigenvector for the symmetric matrix \begin_inset Formula $A=\left[\begin{array}{cc} 2 & -1\\ -1 & 2\end{array}\right]$ \end_inset . \end_layout \begin_layout Standard (a) Find a vector orthogonal to \begin_inset Formula $\mathbf{v}_{1}$ \end_inset and show it is an eigenvector of \begin_inset Formula $A$ \end_inset . \end_layout \begin_layout Standard \begin_inset ERT status collapsed \begin_layout Standard \backslash vspace{2.8in} \end_layout \end_inset (b) ( \series bold Honors students only \series default ) For real eigenvectors \begin_inset Formula $\mathbf{v}_{1}$ \end_inset , \begin_inset Formula $\mathbf{v}_{2}$ \end_inset of a real symmetric matrix \begin_inset Formula $A$ \end_inset corresponding to (real) eigenvalues \begin_inset Formula $\lambda_{1}\neq\lambda_{2}$ \end_inset , we have \begin_inset Formula $\mathbf{v}_{1}^{T}A\mathbf{v}_{2}=\mathbf{v}_{2}^{T}A\mathbf{v}_{1}$ \end_inset . Use this to deduce that \begin_inset Formula $\mathbf{v}_{1}^{T}\mathbf{v}_{2}=0$ \end_inset . \end_layout \end_body \end_document