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Applications of Arzela-Ascoli

Example 1: For $ f \in \mathcal{C}[0,1]$ , let

$\displaystyle (Tf)(x) = \int_0^x f(t) dt $

Then, $ Tf \in \mathcal{C}[0,1]$ , so $ T$ is a linear map from $ \mathcal{C}[0,1]$ to itself. Let

$\displaystyle \mathcal{F}:= \{ Tf : f \in \mathcal{C}[0,1], \Vert f \Vert _\infty \leq 1 \}. $

We would like to see whether $ \mathcal{F}$ is equicontinuous -

$\displaystyle \vert (Tf)(x) - (Tf)(y) \vert = \vert \int_x^y f(t) dt \vert \leq \vert x - y \vert. $

Hence, $ \mathcal{F}$ is an equicontinuous family. Also,

$\displaystyle \vert(Tf)(x)\vert \leq x \leq 1.$

Hence, $ \bar \mathcal{F}$ is compact.

Example 2: (Sketch) -

Theorem 22 (Peano)   Suppose $ D \in \mathbb{R}^2$ is an open set, $ f:D \rightarrow \mathbb{R}$ is continuous, and $ (x_0, y_0) \in D$ . Then the differential equation $ y' = f(x,y)$ has a local solution passing through $ (x_0, y_0)$ .

Proof idea - construct a set of approximations that are equicontinuous, then use the Ascoli-Arzela to show that there is a convergent subsequence. The point where that subsequence converges to is the solution function.



2005-04-15