The Cubic-Linear Linearization Conjecture
Gary H. Meisters
July 1, 1996
1. Keller's Jacobian Conjecture Rephrased
In Section 2 below I state a question, still open, I raised at Curaçao [7] in July 1994. But first some terminology and
background. For vectors x in Cn, let diag(x) denote the diagonal matrix whose diagonal entries are the components
of the vector x. A given n×n complex matrix A serves as the
kernel matrix
for the matrix-valued bilinear function
BA(x, y)
:= 3[diag(Ax)][diag(Ay)]A
defined at the two vector variables x, y ∈ Cn.
An Open Question: Is there an n×n matrix A satisfying both of the following conditions?
Condition 1. The matrix BA(x,x) is nilpotent for all x in Cn. (A is Keller admissible.)
Condition 2. There are distinct vectors x and y in Cn such that BA(x,y)(x - y) = (x - y).
In [6] I called a complex matrix A satisfying both of these conditions
a bad matrix, for want of a better name.
Note 1. The matrix-valued bilinear function
BA(x, y)
has the following properties, which are easily verified:
- BA(x, y)
= BA(y, x) for all vectors x and y.
- BA(x, y) z
= BA(x, z) y
for all vectors x, y and z.
- BA(x, x) is the Jacobian matrix H ′A(x) of the cubic-homogeneous mapping HA(x) :=
[diag(Ax)]3l,
where l denotes the column vector [1,1, . . . ,1]T.
Notice that [diag(Ax)]3l is the same as [diag(Ax)]2Ax.
Note 2. Ott-Heinrich Keller [4] essentially asked the question:
If det [F ′ (x)] ≡ 1 for a polynomial mapping F, is then F bijective with polynomial inverse? It suffices
[1 & 8] to prove injectivity. It even suffices [2] to prove injectivity for the special cubic-linear maps
FA(x) := x -
HA(x) := x -
[diag(Ax)]2Ax.
It was proved in [5, §3.3, p.118] that a polynomial map F
(x) := x - H(x), with H(t x) = t3H(x), is injective if and only if Condition 2
is false. This is a direct consequence of the identity
F(x) - F(y) = (i√3) [ I - B(u, v) ] (u - v)
which is the mean-value formula
F(x) -
F(y) = [ I -
(1/3) B(x, x) + B(x, y) +
B(y, y) ] (x - y)
with the transformation x = au + áv
and y = áu + av, where a = (1 + i√3)/2 and á denotes the complex conjugate of a.
Condition 2 is clearly false if BA(x, y) is nilpotent for all x, y; for then all eigenvalues of
BA(x, y) are zero
for all x, y.
Condition 1 (admissibility) is equivalent to
det [F ′A(x)] ≡ 1, which is necessary for FA to be injective. See [5; Lemma 1(c) p.112 & Eq. (2.2) p.110].
Thus the above open question is just Keller's question rephrased: An answer ``yes'' to our question is ``no'' to Keller's.
2. The Linearization Conjecture for Cubic-Linear Maps
The examples presented in [7] suggest that perhaps The Cubic-Linear Linearization Conjecture is true: Namely,
to each cubic-linear mapping
FA(x) := x - HA(x) := x - [diag(Ax)]2Ax = x - (1/3)BA(x,x )x,
satisfying Condition 1, there corresponds a (normalized) 1-parameter family of homeomorphisms x → hs(x) ≡ h(s, x) of C n which satisfies the Schröder Equation
h(s, sFA(x)) = sh(s,x), with h(s,0) = 0 and ∂xh(s,0) = I,
for all x ∈ Cn and for all complex numbers s with |s| ≠ 1; and so hs conjugates sFA to sI.
In fact, each hs found in [7] is actually a polyomorphism (short for polynomial automorphism) of C
n for all but finitely many complex numbers s on the unit circle. Perhaps each Schröder function hs(x), defined by Schröder's Eq. as a formal power series in x for each |s| ≠ 1, is at least a holomorphic automorphism
of C
n. Furthermore, h0(x) = FA(x) and h&inf;(x) = x, ∀ x ∈ Cn. If this conjecture is true, then Keller's Jacobian Conjecture is true. About two months after the July 1994 Curaçao Conference, Arno van den Essen produced a counterexample [3] to the stronger conjecture (for which I had offered $100 at Curaçao) that the above statement might be true for the even wider class of cubic- homogeneous polynomial maps F(x) = x - H(x) where H(t x) = t3 H(x). Arno collected the $100 by showing that h(s,x), defined by the Schröder Eq. for F(x) = (x1 + p(x)x4, x2 - p(x)x3, x3 + x43, x4) where p(x) = x3x1 + x4x2, can not be polynomial! Even if this Scalar-s Cubic-Linear Linearization Conjecture is not true, there is still the more general (weaker) possibility that the Matrix-S Cubic-Linear Linearization Conjecture is true, where the scalar s is replaced by an invertible matrix S with appropriate eigenvalues. At least we would like to know: For which matrices A does there exist such a matrix S ?
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Department of Mathematics and Statistics
University of Nebraska-Lincoln
Lincoln, NE 68588–0323
gmeister@math.unl.edu
Copyright © 1996 by Gary H. Meisters